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4x^2-24.5x+3=0
a = 4; b = -24.5; c = +3;
Δ = b2-4ac
Δ = -24.52-4·4·3
Δ = 552.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.5)-\sqrt{552.25}}{2*4}=\frac{24.5-\sqrt{552.25}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.5)+\sqrt{552.25}}{2*4}=\frac{24.5+\sqrt{552.25}}{8} $
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